JR wrote on 12/11/13 at 5:18am:
245 pounds falling from a height of 2 feet with acceleration of gravity and an impact distance of say 1/4" would yield an average impact force of ~24,800 pounds force, or ~12,400 per wheel.
This isn't taking in to account the deflection of the tire to ease the impact to the rim itself. Your psi may vary.
...and yes, I'm also bored...
I came up with 23,308 lbs, or 11,654 per wheel. Close enough to yours that we probably used the same equations. But 1/4" impact distance is far too small if you ask me. The majority of that mass is the rider, who bends his legs on landing, absorbing several inches. And any suspension the bike has will also compress.
Additionally, if there's a lander or 'tranny' to the drop, you get additional effective impact deflection of
d=vtTan(Θ) where v is rider speed, t is duration of impact in seconds, and Θ is the lander angle, in radians. Plugging in some numbers I felt were reasonable, I came up with 373 lbf per wheel for a 2' drop to 15° lander. Still significantly lower than any static load hanging from a wall.
I wonder when the trails will open again.